Word: lenhart
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Parke Cummings '25 also reached the semi-finals by defeating P. M. Lenhart '27, number one man on last year's freshman team, 6-4, 7-5. Lenhart was unable to do much with Cummings' service, and this weakness was costly. G. H. Perkins '26 and the winner of the L. H. Gordon '27-G. D. Debevoise '26 match will be the other two semi-finalists. Gordon, captain of the 1927 team, is favored to beat Debevoise. Gordon was seeded number three, while his opponent was number six. Allen will play Perkins, and Cummings will meet the winner...
...Lenhart '27, a seeded player and a member of last year's Freshman team, easily defeated Bernard Bandler '26 yesterday in two sets, 6-1, 6-3. Thayer Cummings '25 defeated J. de Bruyn Kops '25 in a one-sided game, 6-1, 6-0. Though dropping the first set, J. O. Bangs defeated W. S. Stone '26, winning the last two sets by a love score...
...semi-final round of the University doubles tournament played yesterday afternoon at the Divinity Courts, the favorites, Briggs and Harada, and Wheeler and Davies won their matches, although each encounter went to four sets. Wheeler and Davies met last year's Freshman stars, Gordon and Lenhart, in a preliminary engagement to gain their position in the semi-final bracket...
Today the semi-final rounds of the University doubles tournaments will be played off on the Divinity Courts. Wheeler and Davies will meet Gordon and Lenhart in a preliminary match, and the winners will take on Ingraham and Dixon in a semi-final match...
...following men have been seeded in the singles in the order named: Parke Cummings '25, G. H. Perkins '26, L. H. Gordon '27, E. M. Upjohn '25, P. M. Lenhart '27, G. D. Debevoise '26, L. H. Bondi '25, and A. R. Allen...